Solution

Suppose the power of the light source is $P$. Then the intensity of the light falling on the right side of the plate is the same as that at the mirror, i.e. $P/(4\pi f^2)=P/(\pi R^2)$, because light rays reflected from the mirror are parallel to the principal axis as the source is at the focal point. On the other hand, the intensity of the light falling on the left side of the plate is

$$\frac{P}{4\pi(l^2+h^2)}\cos\theta=\frac{Pl}{4\pi(l^2+h^2)^{3/2}}\approx\frac{P}{4l^2},$$

where $\theta$ is the angle between the principal axis and the line joining the source and the plate. Thus, the ratio of the intensities on the left and the right sides of the plate is $(R/(2l))^2$.