6.1.2 | before revision #20483 | Savchenko Solutions

Statement

6.1.2. One cubic centimeter of water was divided into charges with opposite signs and then separated to a distance of 1 m. With what force will the charges attract each other?

Solution

For problem $6.1.2$ — For problem $$6.1.2$$

Answer

$F_e = \frac{\left(53{,}55 \times 10^3\right)^2}{4\pi \times 8{,}85 \times 10^{-12} \times 1^2} \quad \Rightarrow \quad \boxed{F_e = 2{,}58 \times 10^{19} \ \text{N}} \tag{7}$