Calculate the inductance of a long solenoid of radius r and length l placed inside a long superconducting tube of radius R along its axis. Number of turns of the solenoid N.

Solutions of Savchenko Problems in Physics

Aliaksandr Melnichenka
October 2023

    <h3 id="back-link"><a href="/#11.5">$\leftarrow$Back</a></h3>

    <h3> Statement </h3>
    <p>
        $11.5.11^*.$ Calculate the inductance of a long solenoid of radius $r$ and length $l$ placed inside a long superconducting tube of radius $R$ along its axis. Number of turns of the solenoid $N$.

    <h3>Solution</h3>
    <p>
        

The following expressions follow from the figure $$i_\perp=i\cos\alpha$$ $$i_\parallel=i\sin\alpha$$

From the geometry of the solenoid, follows the aspect ratio $$\sin\alpha = \frac{r}{R}$$ $$\cos\alpha = \sqrt{1-\frac{r^2}{R^2}}$$ Ampère's circuital law $$\oint B\\,dl=\mu_0\sum_{k=1}^{N}i_k\Rightarrow B\cdot l=\mu_0 i_\perp N$$ By definition of the magnetic flux $$\left\{\begin{matrix} \Phi=L i \\ \Phi=NBS\cos\alpha \end{matrix}\right.$$ Equating the two equations $$L i=\mu_0 i \cos\alpha \frac{N}{l}NS\cos\alpha$$ $$L=\mu_0 \frac{N^2}{l}S\cos^2 \alpha$$ Given the formula for the area of a circle $S=\pi r^2$, we substitute the value of $\cos\alpha$ $$\boxed{L=\mu_{0}\pi r^{2}\left(1-\frac{r^{2}}{R^{2}}\right)\frac{N^{2}}{l}}$$

    <h4>Answer</h4>
    <p>
        $$L=\mu_{0}\pi r^{2}\left(1-\frac{r^{2}}{R^{2}}\right)\frac{N^{2}}{l}$$
    </p>
    <p style="text-align: right; font-style: italic; font-size: 14;">
      Lutfulloyev Shukurullo<br>
      Physics Department<br>
      National University of Uzbekistan<br>
    </p>


<footer class="row container">
  <br>
    <p>
        <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small>
    </p>
    <p>
        <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> astrosander01@gmail.com <br></small>
    </p>
</footer>