Solution

Statement

$4.2.1.$ Determine the liquid pressure on the bottom surface of a floating puck of cross-section $S$ and mass $m$, if the atmospheric pressure is $P_0$.

Solution

The Archimedes force is equal to the force of gravity:

$$F_A = mg$$

The Archimedes force arises from the difference in pressure from different sides on the same area, therefore:

$$(P - P_0)S = mg$$

We get the answer:

$$P = \frac{mg}{S} + P_0$$