A wedge has a slope's angle of 30^\circ. A vertical rod goes down with velocity v and pushes the wedge. What velocity will develope the wedge?
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<h3> Statement </h3>
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$1.5.3$
A wedge has a slope's angle of 30$^\circ$. A vertical rod goes down with velocity $v$ and pushes the wedge. What velocity will develope the wedge?
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<img src="statement.png"
loading="lazy" alt="1.5.3" width="200" />
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For problem 1.5.3
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<h3>Solution</h3>
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Firstly, we suppose there is no any friction. For a better understanding of the problem, consider the following figure
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<center><figure><img
src="1.5.3.png" loading="lazy" alt="1.5.3" width="200" />
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Motion of wedge and rod
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According to figure
$$\tan{30^\circ}=\frac{S_r}{S_w}$$
and this relation is valid for velocities too because the motion is uniform (at constant speed)
$$\tan{30^\circ}=\frac{v}{v_w}=\frac{\sqrt{3}}{3}$$
So, separating $v_w$
$$\boxed{v_w=v\sqrt{3}}$$
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<p style="text-align: right; font-style: italic; font-size: 14;">
BSc. Luis Daniel Fernández Quintana<br>
Physics Department (FCNE)<br>
Universidad de Oriente, Cuba<br>
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