Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.
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<h3> Statement </h3>
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$4.2.14$
Determine the pressure force of the logs of mass $m$ on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.
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<img src="statement.png"
loading="lazy" alt="4.2.14" width="300" />
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For problem 4.2.14
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<h3>Solution</h3>
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Let's consider the following figure
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<img src="draw.png"
loading="lazy" alt="4.2.14" width="550" />
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Force analysis
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From right figure
$$\cos{\theta} = \frac{R}{2R} = 0.5$$
so, $\theta = 60^\circ$. Applying Newton Second Law for submerged trunk on $x$-axis,
$$N = N_t\~\sin{\theta} \\;(1)$$
on $y$-axis
$$F_{A1} = mg + N_t\~\cos{\theta}$$
$$\rho_w\~g\~V = mg + N_t\~\cos{\theta} \\;(2)$$
For half-submerged trunk, on $x$-axis,
$$N = N_t\~\sin{\theta}$$
on $y$-axis
$$F_{A2} + N_t\~\cos{\theta} = mg$$
$$\rho_w\~g\~\frac{V}{2} + N_t\~\cos{\theta} = mg \\;(3)$$
Substituting $(2)$ into $(3)$, it is obtained
$$N_t = \frac{mg}{3\~\cos{\theta}} \\;(4)$$
Putting $(4)$ into $(1)$
$$N = \frac{mg}{3}\~\tan{\theta}$$
$$\boxed{N = \frac{mg}{\sqrt{3}}}$$
Note: You can prove that both pressure forces generated by trunks are equals.
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<p style="text-align: right; font-style: italic; font-size: 14;">
BSc. Luis Daniel Fernández Quintana<br>
Physics Department (FCNE)<br>
Universidad de Oriente, Cuba<br>
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