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Statement

$13.3.4.$ At what distance from the lens is the object located, if the distance between the object and its actual image is minimal? The focal length of the lens is $f$.

Solution

For a thin len,
$\frac{1}{s}+\frac{1}{s'} = \frac{1}{f}$
as the distance between the object and its actual image is minimal, $s = s'$,
$\frac{2}{s} = \frac{1}{f}$
$s = 2f$

Answer

$s = 2f$

Contributed by @Luisito · Last updated Jun 11, 2026
Last edited Luisito , Jun 11, 2026
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Discussion

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