<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="description" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<meta property="og:title" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
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<meta property="og:description" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<title>The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.</title>
$2.1.37.$ The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: $f = A \rho_0 r^2 v^2$, where $\rho_0 \approx 1.3$$\frac{kg}{m^3}$ is the air density, and the dimensionless coefficient A for round drops is of the order of $1$. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius $r = 1$ mm when it falls from a great height.
There are two forces acting on a falling drop: the constant force of gravity, which accelerates the movement of the drop, and the force of air resistance, which slows its movement and increases with the speed of the drop. The force of air resistance increases until it becomes equal to the force of gravity. Then the change in speed stops, and the drop falls at a constant speed.
@@ -70,21 +70,21 @@
</p>
<p>
Let's write the equation after a long period of time:
−
$$ mg=Aρ_0r^2v^2\;(1) $$
+
$$ mg=A\rho_0r^2v^2\quad(1) $$
Let's find $m$ through the volume $V$:
−
$$ m=ρV=\frac{4}{3}ρ\pi r^3 $$
+
$$ m=\rhoV=\frac{4}{3}\rho\pi r^3 $$
And we substitute into $(1)$:
−
$$\frac{4}{3}ρ \pi r^3 g=Aρ_0r^2v^2 $$
+
$$\frac{4}{3}\rho\pi r^3 g=A\rho_0r^2v^2 $$
From here:
−
$$\boxed{v = \sqrt{\frac{4}{3}ρ \pi r g \cdot\frac{1}{Aρ_0}}≈5.5\,\frac{\text{m}}{\text{s}}\;(2)}$$
+
$$\boxed{v = \sqrt{\frac{4}{3}\rho\pi r g \cdot\frac{1}{A\rho _0}}\approx5.5\,\frac{\text{m}}{\text{s}}\quad(2)}$$
From $(2)$, the larger $r$, the larger $v$. This means that larger drops fall
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="description" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<meta name="description" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<meta property="og:title" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<meta property="og:title" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<meta property="og:image" content="img/logo.png">
<meta property="og:image" content="img/logo.png">
<meta property="og:description" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<meta property="og:description" content="The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.">
<title>The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.</title>
<title>The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: f = A \rho_0 r^2 v^2, where \rho_0 \approx 1.3 \frac{kg}{m^3} is the air density, and the dimensionless coefficient A for round drops is of the order of 1. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius r = 1 mm when it falls from a great height.</title>
$2.1.37.$ The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: $f = A \rho_0 r^2 v^2$, where $\rho_0 \approx 1.3$$\frac{kg}{m^3}$ is the air density, and the dimensionless coefficient A for round drops is of the order of $1$. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius $r = 1$ mm when it falls from a great height.
$2.1.37.$ The force of air resistance acting on raindrops is proportional to the product of the square of the droplet velocity and the square of their radius: $f = A \rho_0 r^2 v^2$, where $\rho_0 \approx 1.3$$\frac{kg}{m^3}$ is the air density, and the dimensionless coefficient A for round drops is of the order of $1$. Which drops, large or small, fall to the ground with faster speed? Estimate the velocity of a drop of radius $r = 1$ mm when it falls from a great height.
There are two forces acting on a falling drop: the constant force of gravity, which accelerates the movement of the drop, and the force of air resistance, which slows its movement and increases with the speed of the drop. The force of air resistance increases until it becomes equal to the force of gravity. Then the change in speed stops, and the drop falls at a constant speed.
There are two forces acting on a falling drop: the constant force of gravity, which accelerates the movement of the drop, and the force of air resistance, which slows its movement and increases with the speed of the drop. The force of air resistance increases until it becomes equal to the force of gravity. Then the change in speed stops, and the drop falls at a constant speed.
@@ -70,21 +70,21 @@
</p>
</p>
<p>
<p>
Let's write the equation after a long period of time:
Let's write the equation after a long period of time:
$$ mg=Aρ_0r^2v^2\;(1) $$
$$ mg=A\rho_0r^2v^2\quad(1) $$
Let's find $m$ through the volume $V$:
Let's find $m$ through the volume $V$:
$$ m=ρV=\frac{4}{3}ρ\pi r^3 $$
$$ m=\rhoV=\frac{4}{3}\rho\pi r^3 $$
And we substitute into $(1)$:
And we substitute into $(1)$:
$$\frac{4}{3}ρ \pi r^3 g=Aρ_0r^2v^2 $$
$$\frac{4}{3}\rho\pi r^3 g=A\rho_0r^2v^2 $$
From here:
From here:
$$\boxed{v = \sqrt{\frac{4}{3}ρ \pi r g \cdot\frac{1}{Aρ_0}}≈5.5\,\frac{\text{m}}{\text{s}}\;(2)}$$
$$\boxed{v = \sqrt{\frac{4}{3}\rho\pi r g \cdot\frac{1}{A\rho _0}}\approx5.5\,\frac{\text{m}}{\text{s}}\quad(2)}$$
From $(2)$, the larger $r$, the larger $v$. This means that larger drops fall
From $(2)$, the larger $r$, the larger $v$. This means that larger drops fall
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
