Updated greek laters @ latex compiling

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<h4>Answer</h4>
<p>
− The moment of velocity (vector product of velocity and radius vector drawn from the center of orbit) of the probe is the same as the moment of velocity of the station; if the probe and station rotate by the same angle, the velocity vectors will change equally. From the constancy of the moment of velocity of the probe: $up = (v − V \sin α)r$ it follows that $r = p/(1 − ε \sin α)$, where $ε = V /u$. For $ε < 1$ the trajectory of the probe is an ellipse, for $ε = 1$ it is a parabola, for $ε > 1$ it is a hyperbola.
+ The moment of velocity (vector product of velocity and radius vector drawn from the center of orbit) of the probe is the same as the moment of velocity of the station; if the probe and station rotate by the same angle, the velocity vectors will change equally. From the constancy of the moment of velocity of the probe: $up = (v − V \sin\alpha )r$ it follows that $r = p/(1 − \varepsilon \sin\alpha )$, where $\varepsilon = V /u$. For $\varepsilon < 1$ the trajectory of the probe is an ellipse, for $\varepsilon = 1$ it is a parabola, for $\varepsilon > 1$ it is a hyperbola.
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Alisher Yerkebayev<br>
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