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| Solutions of Savchenko Problems in Physics <br> | | Solutions of Savchenko Problems in Physics <br> |
| <i><b>knowledge must be free</b></i> | | <i><b>knowledge must be free</b></i> |
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| <h3 id="back-link"><a href="../../#3.2">$\leftarrow$Back</a></h3> | | <h3 id="back-link"><a href="../../#3.2">$\leftarrow$Back</a></h3> |
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| <h3> Statement </h3> | | <h3> Statement </h3> |
| <p> | | <p> |
| $3.2.7.$ a. A mathematical pendulum - an iron ball of mass $m$ hanging on a long string - has a period $T_0$. In the presence of a magnet placed slightly below the ball, the period of oscillation became equal to $T$. Determine the magnetic force acting on the ball.</p><p> | | $3.2.7.$ a. A mathematical pendulum - an iron ball of mass $m$ hanging on a long string - has a period $T_0$. In the presence of a magnet placed slightly below the ball, the period of oscillation became equal to $T$. Determine the magnetic force acting on the ball.</p><p> |
| b. An iron pendulum ball is placed between the poles of a magnet so that a horizontal magnetic force acts on it. Find this force and the new equilibrium position of the ball if the period of its oscillations after the magnetic field is switched on becomes equal to $T$. | | b. An iron pendulum ball is placed between the poles of a magnet so that a horizontal magnetic force acts on it. Find this force and the new equilibrium position of the ball if the period of its oscillations after the magnetic field is switched on becomes equal to $T$. |
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| For problem $3.2.7$ | | For problem $3.2.7$ |
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| <h3>Solution</h3> | | <h3>Solution</h3> |
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| $$ \frac{T^{2}}{T_{0}^{2}}=\frac{mg}{mg + F} \Rightarrow \fbox{$F =\frac{mg(T_{0}^{2}-T^{2})}{T^{2}}$} $$ | | $$ \frac{T^{2}}{T_{0}^{2}}=\frac{mg}{mg + F} \Rightarrow \fbox{$F =\frac{mg(T_{0}^{2}-T^{2})}{T^{2}}$} $$ |
| b) For the second case, we write the equation of harmonic oscillations | | b) For the second case, we write the equation of harmonic oscillations |
| $$ m\ddot{x}=- \left(\sqrt{(mg)^{2} + F^{2}}\right)\sin\varphi $$ | | $$ m\ddot{x}=- \left(\sqrt{(mg)^{2} + F^{2}}\right)\sin\varphi $$ |
| Given the approximation value $\sin\varphi =\frac{x}{l}$ | | Given the approximation value $\sin\varphi =\frac{x}{l}$ |
| $$ m\ddot{x} = - \left(\sqrt{(mg)^{2} + F^{2}}\right)\cdot\frac{x}{l} $$ | | $$ m\ddot{x} = - \left(\sqrt{(mg)^{2} + F^{2}}\right)\cdot\frac{x}{l} $$ |
| Solving the equation of harmonic oscillations of the form $\ddot{x}+\omega^2x=0$, we obtain the angular frequency | | Solving the equation of harmonic oscillations of the form $\ddot{x}+\omega^2x=0$, we obtain the angular frequency |
| $$ \omega =\sqrt{\frac{\sqrt{(mg)^{2}+F^{2}}}{ml}} $$ | | $$ \omega =\sqrt{\frac{\sqrt{(mg)^{2}+F^{2}}}{ml}} $$ |
| Similarly, substituting into $(1)$ | | Similarly, substituting into $(1)$ |
| $$ \frac{T_{0}^{4}}{T^{4}} = \frac{(mg)^{2}+ F^{2}}{(mg)^{2}} \Rightarrow \fbox{$F = mg\sqrt{\frac{T_{0}^{4}-T^{4}}{T^{4}}}$} $$ | | $$ \frac{T_{0}^{4}}{T^{4}} = \frac{(mg)^{2}+ F^{2}}{(mg)^{2}} \Rightarrow \fbox{$F = mg\sqrt{\frac{T_{0}^{4}-T^{4}}{T^{4}}}$} $$ |
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| <p style="text-align: right; font-style: italic; font-size: 14;"> | | <p style="text-align: right; font-style: italic; font-size: 14;"> |
| Dzikan Mikita<br> | | Dzikan Mikita<br> |
| Aliaksandr Kanashenka | | Aliaksandr Kanashenka |
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| </p> | | </p> |
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| <h4>Answer</h4> | | <h4>Answer</h4> |
| <p> | | <p> |
| $$F =\frac{mg(T_{0}^{2}-T^{2})}{T^{2}};\quad F = mg\sqrt{\frac{T_{0}^{4}-T^{4}}{T^{4}}}$$ | | $$F =\frac{mg(T_{0}^{2}-T^{2})}{T^{2}};\quad F = mg\sqrt{\frac{T_{0}^{4}-T^{4}}{T^{4}}}$$ |
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