Updated spacing between @ latex expressions

astrosander edited
View solution History
revision #10264 parent #10055 GitHub c702ebe ← older newer →
en/2.1.23.md +9 −9
@@ -6,14 +6,14 @@
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="content-language" content="en">
<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
− <meta name="description" content="A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu. Find the acceleration of the body if it does not detach from the plane.">
+ <meta name="description" content="A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu . Find the acceleration of the body if it does not detach from the plane.">
<meta name="author" content="Aliaksandr Melnichenka">
<meta name="date" content="2023-10" scheme="YYYY-MM">
− <meta property="og:title" content="A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu. Find the acceleration of the body if it does not detach from the plane.">
+ <meta property="og:title" content="A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu . Find the acceleration of the body if it does not detach from the plane.">
<meta property="og:image" content="img/logo.png">
− <meta property="og:description" content="A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu. Find the acceleration of the body if it does not detach from the plane.">
+ <meta property="og:description" content="A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu . Find the acceleration of the body if it does not detach from the plane.">
<meta name="yandex-verification" content="6cfda41f74038368">
− <title>A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu. Find the acceleration of the body if it does not detach from the plane.</title>
+ <title>A body of mass m lying on a horizontal plane is affected by a force F at an angle \alpha to the horizon. Coefficient of friction \mu . Find the acceleration of the body if it does not detach from the plane.</title>
<link rel="stylesheet" href="../../css/css-latex/style.css">
<link rel="icon" href="../../img/logo.png" type="image/png">
<script src="../../js/jquery-1.10.1.min.js"></script>
@@ -78,28 +78,28 @@
The friction force is determined as:
</p>
<p style="text-align: center;">
−$F_{тре} = (mg-F \,\sin \alpha)$
+$F_{тре} = (mg-F \,\sin\alpha )$
</p>
<p>
2. The basic law of dynamics, therefore. will be written as follows:
</p>
<p style="text-align: center;">
−$F \, \cos \,\alpha = \mu (mg-F \,\sin \alpha)$
+$F \, \cos\alpha = \mu (mg-F \,\sin\alpha )$
</p>
<p>
3. From the equation of Newton's second law it is easy to determine the desired acceleration
</p>
<p style="text-align: center;">
−$a = \frac{1}{m}(F\cos\alpha-\mu mg+F\,\sin \alpha)$
+$a = \frac{1}{m}(F\cos\alpha -\mu mg+F\,\sin\alpha )$
</p>
<p style="text-align: center;">
−$a = \frac{F}{m}(\cos\alpha-\mu \,\sin \alpha)$
+$a = \frac{F}{m}(\cos\alpha -\mu\,\sin\alpha )$
</p>
</p>
<h4>Answer</h4>
<p>
− $a = (F/m)(\cos \,\alpha + \mu \,\sin \varphi)$$ − \mu g$ if this expression is greater than zero, otherwise $a = 0$.
+ $a = (F/m)(\cos\alpha + \mu\,\sin\varphi)$$ − \mu g$ if this expression is greater than zero, otherwise $a = 0$.
</p>
unchanged lines 12