Updated spacing between @ latex expressions

astrosander edited
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revision #10367 parent #9951 GitHub c702ebe ← older newer →
en/1.3.12.md +4 −4
@@ -56,17 +56,17 @@
<h3>Solution</h3>
<p>
<p>First, let's determine the flight time of each water drop. This time is:</p>
−$$ t = \frac{2v_0 \cdot \sin \alpha}{g} $$
+$$ t = \frac{2v_0 \cdot \sin\alpha}{g} $$
<p>There is water in the air, flowing out of the hose in exactly time $t$. The mass of this water is easy to determine: it is the mass of water in a cylinder of height $v_0 t$ and base area $S$.</p>
−$$ m = \rho S v_0 t = \rho S \frac{2v_0^2 \cdot \sin \alpha}{g} $$
+$$ m = \rho S v_0 t = \rho S \frac{2v_0^2 \cdot \sin\alpha}{g} $$
−$$ m = \frac{2 \rho v_0^2 S \cdot \sin \alpha}{g} = 7.2 \text{ kg}. $$
+$$ m = \frac{2 \rho v_0^2 S \cdot \sin\alpha}{g} = 7.2 \text{ kg}. $$
</p>
<h4>Answer</h4>
<p>
− $$x = \frac{2\nu ^{2}}{g(\tan\beta +\tan\alpha )}$$
+ $$x = \frac{2\nu^{2}}{g(\tan\beta +\tan\alpha )}$$
</p>
unchanged lines 12