Updated spacing between @ latex expressions

astrosander edited
View solution History
revision #10444 parent #9706 GitHub c702ebe ← older newer →
en/1.4.7.md +9 −9
@@ -66,49 +66,49 @@
For the plane to fly on course, the following conditions must be met
</p>
<p class="exp">
−$$u \sin \alpha = v \sin \beta$$
+$$u \sin\alpha = v \sin\beta$$
</p>
<p >
Where from
</p>
<p class="exp">
−$$\cos \beta = \sqrt{1 - u^2 \sin ^2 \alpha / v^2}$$
+$$\cos\beta = \sqrt{1 - u^2 \sin^2 \alpha / v^2}$$
</p>
<p >
And the total time there and back
</p>
<p class="exp">
−$$ t_1 = \frac{L}{v \cos \beta + u \cos \alpha} $$
+$$ t_1 = \frac{L}{v \cos\beta + u \cos\alpha} $$
</p>
<p class="exp">
−$$ t_2 = \frac{L}{v\cos \beta - u \cos \alpha} $$
+$$ t_2 = \frac{L}{v\cos\beta - u \cos\alpha} $$
</p>
<p >
We find the full time as
</p>
<p class="exp">
$$t=t_1+t_2$$
</p>
<p >
−Substitute the value of $\cos \beta$:
+Substitute the value of $\cos\beta$:
</p>
<div class="scroll-wrapper">
<p class="exp">
−$$ t=\frac{L}{\sqrt{v^2 - u^2 \sin ^2 \alpha } + u \cos \alpha} + \frac{L}{\sqrt{v^2 - u^2 \sin ^2 \alpha} - u \cos \alpha} $$
+$$ t=\frac{L}{\sqrt{v^2 - u^2 \sin^2 \alpha} + u \cos\alpha} + \frac{L}{\sqrt{v^2 - u^2 \sin^2 \alpha} - u \cos\alpha} $$
</p>
<p class="exp">
−$$ t=L\frac{\sqrt{v^2 - u^2 \sin ^2 \alpha }+\sqrt{v^2 - u^2 \sin ^2 \alpha} }{(\sqrt{v^2 - u^2 \sin ^2 \alpha} + u \cos \alpha)(\sqrt{v^2 - u^2 \sin ^2 \alpha} - u \cos \alpha)} $$
+$$ t=L\frac{\sqrt{v^2 - u^2 \sin^2 \alpha}+\sqrt{v^2 - u^2 \sin^2 \alpha} }{(\sqrt{v^2 - u^2 \sin^2 \alpha} + u \cos\alpha )(\sqrt{v^2 - u^2 \sin^2 \alpha} - u \cos\alpha )} $$
</p>
<p class="exp">
−$$ t=\frac{2L\sqrt{v^2 - u^2 \sin ^2 \alpha }}{(\sqrt{v^2 - u^2 \sin ^2 \alpha} + u \cos \alpha)(\sqrt{v^2 - u^2 \sin ^2 \alpha} - u \cos \alpha)} $$
+$$ t=\frac{2L\sqrt{v^2 - u^2 \sin^2 \alpha}}{(\sqrt{v^2 - u^2 \sin^2 \alpha} + u \cos\alpha )(\sqrt{v^2 - u^2 \sin^2 \alpha} - u \cos\alpha )} $$
</p>
</div>
<p >
Expressing the required time:
</p>
<p class="exp">
−$$ \fbox{$t=\frac{2L\sqrt{v^2 - u^2 \sin ^2 \alpha }}{v^{2}-u^{2}}$} $$
+$$ \fbox{$t=\frac{2L\sqrt{v^2 - u^2 \sin^2 \alpha}}{v^{2}-u^{2}}$} $$
</p>
</p>
unchanged lines 18