Translated 9.1.1-9.1.5

astrosander edited
revision #11403 GitHub fb5d7ac
@@ -0,0 +1,87 @@
+<!DOCTYPE html>
+<html lang="en">
+
+<head>
+ <meta charset="utf-8">
+ <meta name="viewport" content="width=device-width, initial-scale=1.0">
+ <meta http-equiv="content-language" content="en">
+ <meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
+ <meta name="description" content="A charge of 1 C moving at a speed of 1 \text{ m/s} in a magnetic field is acted upon by a force of 10 N. The charge moves at an angle of 30^{\circ} to the direction of the magnetic field induction. What is the induction of this field?">
+ <meta name="author" content="Aliaksandr Melnichenka">
+ <meta name="date" content="2023-10" scheme="YYYY-MM">
+ <meta property="og:title" content="A charge of 1 C moving at a speed of 1 \text{ m/s} in a magnetic field is acted upon by a force of 10 N. The charge moves at an angle of 30^{\circ} to the direction of the magnetic field induction. What is the induction of this field?">
+ <meta property="og:image" content="img/logo.png">
+ <meta property="og:description" content="A charge of 1 C moving at a speed of 1 \text{ m/s} in a magnetic field is acted upon by a force of 10 N. The charge moves at an angle of 30^{\circ} to the direction of the magnetic field induction. What is the induction of this field?">
+ <meta name="yandex-verification" content="6cfda41f74038368">
+ <title>A charge of 1 C moving at a speed of 1 \text{ m/s} in a magnetic field is acted upon by a force of 10 N. The charge moves at an angle of 30^{\circ} to the direction of the magnetic field induction. What is the induction of this field?</title>
+ <link rel="stylesheet" href="https://savchenkosolutions.com/css/css-latex/style.css">
+ <link rel="icon" href="https://savchenkosolutions.com/img/logo.png" type="image/png">
+ <script src="https://savchenkosolutions.com/js/jquery-1.10.1.min.js"></script>
+ <script async src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.7/MathJax.js?config=TeX-MML-AM_CHTML"></script>
+ <script type="text/x-mathjax-config">
+ MathJax.Hub.Config({
+ extensions: ['tex2jax.js'],
+ jax: ['input/TeX', 'output/HTML-CSS'],
+ tex2jax: {
+ inlineMath: [['$', '$'], ['$', '$']],
+ processEscapes: true,
+ processClass: 'tex2jax',
+ ignoreClass: 'html'
+ },
+ showProcessingMessages: false,
+ messageStyle: 'none'
+ });
+ </script>
+</head>
+ <body style="">
+ <header style="text-align:center;">
+ <a href="../../" style="text-decoration: none;">
+ <div id="logo">
+ <span><img src="../../img/book.png"></span><span>Savchenko Solutions</span>
+ </div>
+ </a>
+ <p class="author">
+ Solutions&nbsp;of&nbsp;Savchenko Problems&nbsp;in&nbsp;Physics <br>
+ <i><b>knowledge must be free</b></i>
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../../#9.1">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $9.1.2.$ A charge of $1$ C moving at a speed of $1 \text{ m/s}$ in a magnetic field is acted upon by a force of $10$ N. The charge moves at an angle of $30^{\circ}$ to the direction of the magnetic field induction. What is the induction of this field?
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ Lorentz force acting on a moving particle in a magnetic field
+$$ \vec{F} = q(\vec{v}\times \vec{B}) $$
+rewriting in scalar form we get
+$$ F = qvB\sin\alpha $$
+where $\alpha$ is the angle between $\vec{B}$ and $\vec{v}$ </p><p>
+Substituting the values ​​from the condition, we get
+$$ \boxed{{B} = \frac{F}{qv \sin\alpha} = 20 \text{ T}} $$
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $${B} = \frac{F}{qv \sin\alpha} = 20 \text{ T}$$
+ </p>
+ <p style="text-align: right; font-style: italic; font-size: 14;">
+ Andrei Yersh<br>
+ </p>
+
+
+ <footer class="row container">
+ <br>
+ <p>
+ <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small>
+ </p>
+ <p>
+ <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
+ </p>
+ </footer>
+ </body>
+
+</html>