Translated 9.1.1-9.1.5

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+ <h3 id="back-link"><a href="../../#9.1">$\leftarrow$Back</a></h3>
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+ <h3> Statement </h3>
+ <p>
+ $9.1.1.$ A force of 15 N acts on a linear conductor of length $10$ cm, located perpendicular to a magnetic field, if the current in the conductor is $1.5$ A. Find the induction of the magnetic field.
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ We find the Ampere force as
+$$ \vec{F} = (\vec{Il})\times \vec{B} $$
+In scalar form, this expression can be rewritten as
+$$ F = B\cdot Il \cdot \sin\alpha\quad(1) $$
+since the field is perpendicular to the current element, then
+$$ \alpha =90^{\circ};\quad \sin\alpha =1 $$
+From here, we rewrite the expression $(1)$ as
+$$ F = B \cdot Il \Rightarrow \boxed{B = \frac{F}{Il} = 100\text{ T}} $$
+
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $$B = \frac{F}{Il} = 100\text{ T}$$
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