Edit to “Solution”

astrosander edited
revision #11814 parent #9275 ← older newer →
@@ -10,7 +10,7 @@Solution
a) Based on the results from [2.1.15](../../2/2.1.15), we found that when springs are connected in parallel, their equivalent stiffness $$ k'=k_1+k_2 $$ Substituting into $(1)$: $$ T_1=2\pi\sqrt{\frac{m}{k_1+k_2}} $$ b) Alternatively, from [2.1.16](../2.1.16), we obtained that when springs are connected in parallel, their equivalent stiffness is $$ k'=\frac{k_1\cdot k_2}{k_1+k_2} $$ Substituting into $(1)$: $$ T_2=2\pi\sqrt{\frac{m(k_1+k_2)}{k_1\cdot k_2}} $$ c) Also in [2.1.16](../2.1.16), we showed that this scheme is equivalent to the case of parallel connection of springs
−![ Part of the solution from 2.1.16 |1153x419, 67%](../../img/3.2.4/3.2.4_1.png) Part of the solution from [2.1.16](../2.1.16)
+![ Part of the solution from $2.1.16$ |1153x419, 67%](../../img/3.2.4/3.2.4_1.png)
Equivalent spring stiffness $$ k'=k_1+k_2 $$ Substituting into $(1)$: $$ T_3=2\pi\sqrt{\frac{m}{k_1+k_2}} $$
unchanged lines 3