$\leftarrow$Back

  <h4>Statement</h4>
  <p>
    $1.5.3$
    A wedge has a slope's angle of 30$^\circ$. A vertical rod goes down with velocity $v$ and pushes the wedge. What velocity will develope the wedge?
  </p>
  <center>
    <figure>
      <img src="statement.png"
        loading="lazy" alt="1.5.3" width="200" />
      <figcaption>
        For problem 1.5.3
      </figcaption>
    </figure>
  </center>
  <h4>Solution</h4>
   <p class="TxtSolutions">
    Firstly, we suppose there is no any friction. For a better understanding of the problem, consider the following figure
   </p>
    <center>
      <figure>
        <img src="1.5.3.png"
          loading="lazy" alt="1.5.3" width="200" />
        <figcaption>
          Motion of wedge and rod
        </figcaption>
      </figure>
    </center>
    <p class="TxtSolutions">
      According to figure
    </p>
    <center>
        $\tan{30^\circ}=\frac{S_r}{S_w}$
    </center>
    <p class="TxtSolutions">
      and this relation is valid for velocities too because the motion is uniform (at constant speed)
    </p>
    <center>
      $\tan{30^\circ}=\frac{v}{v_w}=\frac{\sqrt{3}}{3}$
    </center>
    So, separating $v_w$
    <center>
      $\boxed{v_w=v\sqrt{3}}$
    </center>
    <p class="TxtSolutions" style="text-align: right; font-style: italic; font-size: 14;">   
        BSc. Luis Daniel Fernández Quintana<br>
        Physics Department (FCNE)<br>
        Universidad de Oriente, Cuba<br>
      </p>
</article>