Edits to “Statement”, “Solution”, “Answer”

giorgiotinashvili edited
revision #14446 parent #14443 ← older newer →
@@ -1,13 +1,29 @@
### Statement
−$10.1.1.$ [Insert the problem statement]
+$10.1.1.$ A proton accelerated by a voltage of 20 kV enters a uniform magnetic field
+with an induction of 0.1 T perpendicular to the field. Find the radius of the
+circle along which the proton moves in the magnetic field.
+
### Solution
+Using:
−![For problem $10.1.1$ |599x939, 31%](../../img/10.1.1/scan-0.png)
+\[
+\frac{1}{2}mv^2 = q, \hspace{0.5cm} r=\frac{mv}{qB}
+\]
+With:
+\[q=1.6 \times 10^{-19}C, \hspace{0.5cm} m=1.67 \times 10^{-27}kg, \hspace{0.5cm} V=20kV, \hspace{0.5cm} B=0.10T\]
+We get:
+\[
+v= \sqrt{\frac{2qV}{m}} \approx 1.96 \times 10^6 \, \mathrm{m/s}
+\]
+\[r \approx 0.2\,\mathrm{m} \]
+
#### Answer
−[Insert a concise answer or boxed result]
+\[
+\boxed {\, r \approx 0.2m \,}
+\]