Edits to “Statement”, “Solution”, “Answer”

astrosander edited
revision #15875 parent #15855 ← older
@@ -1,1 +1,35 @@
−@@sUf04
+### Statement
+
+$1.1.10^*.$ A bus is driving along a straight highway at constant speed $v$. You have noticed the bus when it was at some point $A$. From what area near the highway can you catch up with this bus if your running speed is $u < v$? Draw this area for $u = v/2$.
+
+![ For problem $1.1.10^*$ |604x409, 39%](../../img/1.1.10/statement.png)
+
+### Solution
+
+![ Chasing a bus |632x365, 37%](../../img/1.1.10/1.1.10.png)
+
+1\. Let the bus is at point $A$, and the catching up person starts from point $B$ and runs perpendicular to the roadway $AC$. Let us introduce the notations: $AC = L, BC = h, AB = s.$
+
+![ The plane bounded by $\alpha$ |349x306, 34%](../../img/1.1.10/sol.png)
+
+2\. From right-angled triangle $ABC$ we have
+
+$$
+L = s \cdot \cos\frac{\alpha}{2};\quad h = s \cdot\sin\frac{\alpha}{2}
+$$
+
+3\. Travel time of bus $t_1$ and passenger $t_2$ before meeting at point $C$
+
+$$
+{t}_{1}=\frac{{L}}{{v}}=\frac{{s}\cos(\alpha /2)}{{v}};\quad{t}_{2}=\frac{{h}}{{u}}=\frac{{s}\sin(\alpha /2)}{{u}}
+$$
+
+where from
+
+$$
+\fbox{$\alpha = 2 \cdot \arctan \frac{u}{v}$}
+$$
+
+#### Answer
+
+From the region bounded by the angle $\alpha = 2 \arctan (u/v)$ with vertex at the point $A$, bisected by the motorway