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Statement

2.5.37. A bullet of mass m, having an initial velocity v, penetrates a load of the same
mass m suspended on a thread and gets stuck in the second one of the same
size. Find the amount of heat released in the first load, if the amount of heat
released in the second load is Q2. Ignore the time of interaction of the bullet
with the load.

For problem $2.5.37$

Solution

For problem $2.5.37$
For problem
For problem $2.5.37$
For problem
For problem $2.5.37$
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Answer

Q2 is <0 , so our answer is:

Q1 = -4Q2 + mv(-4Q2/m)^(1/2)