Edits to “Statement”, “Solution”, “Answer”

astrosander edited
revision #15931 parent #15930 ← older
@@ -1,27 +1,17 @@
### Statement
−$2.5.37.$ A bullet of mass m, having an initial velocity v, penetrates a load of the same
−mass m suspended on a thread and gets stuck in the second one of the same
−size. Find the amount of heat released in the first load, if the amount of heat
−released in the second load is Q2. Ignore the time of interaction of the bullet
−with the load.
+$2.5.37.$ A bullet of mass $m$, having an initial velocity $v$, penetrates a load of the same mass m suspended on a thread and gets stuck in the second one of the same size. Find the amount of heat released in the first load, if the amount of heat released in the second load is $Q_2$. Ignore the time of interaction of the bullet with the load.
### Solution
−![For problem $2.5.37$ |1278x1474, 31%](../../img/2.5.37/scan-2.png)
+![For problem $2.5.37$ |1278x1474, 100%](../../img/2.5.37/scan-2.png)
−![For problem $2.5.37$ |1156x1656, 31%](../../img/2.5.37/scan-1.png)
+![For problem $2.5.37$ |1156x1656, 100%](../../img/2.5.37/scan-1.png)
−![For problem $2.5.37$ |1046x900, 31%](../../img/2.5.37/scan-0.png)
+![For problem $2.5.37$ |1046x900, 100%](../../img/2.5.37/scan-0.png)
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#### Answer
−Q2 is <0 , so our answer is:
+$Q_2$ is $<0$ , so our answer is:
−Q1 = -4Q2 + mv(-4Q2/m)^(1/2)
+$$Q_1 = -4Q_2 + mv(-4Q_2/m)^{1/2}$$