New solution

naz edited
revision #18622 newer →
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+### Statement
+
+$9.4.3.$ [Insert the problem statement]
+
+### Solution
+
+We know that a plane with linear current density $i$ creates a uniform field around itself, its value $$B=\frac{\mu_0 i}{2}$$
+, but we don't really need it.
+
+Consider an arbitrary closed surface. The stream is by definition equal to:
+$$\oint_S\hat{B}\cdot d\hat{S}$$
+
+The definition of vector divergence will be useful to us.:
+$$div \hat{a} = {lim}_{\Delta V\to0} \frac{1}{\Delta V}\oint_S \hat{a}\cdot d\hat{S}=\frac{\partial a}{\partial x}+\frac{\partial a}{\partial y} + \frac{\partial a}{\partial z}$$
+
+Note for now that the second definition and uniformity of the field implies $$div\hat{B}=0$$
+in the whole space
+
+Now let's break down the volume that borders our surface into many infinitely small volumes $dV$. From the first definition of divergence, an alternative expression for the flow can be obtained:
+$$\Phi = \int_V div \hat{B} dV$$
+
+Because the divergence is zero at any point in space.: $\to$ $$\Phi=0$$
+
+#### Answer
+
+[Insert a concise answer or boxed result]