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en/11.3.18.md
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| + | ### Statement | ||
| + | |||
| + | $11.3.18.$ [Insert the problem statement] | ||
| + | |||
| + | ### Solution | ||
| + | |||
| + | In an ideal transformer (ideal means no losses, no leakage, and infinite magnetic permeability) | ||
| + | |||
| + | the voltage induced in each winding is proportional to the number of turns | ||
| + | |||
| + | $ V_1 = N_1 \frac{d\Phi}{dt}, V_2 = N_2 \frac{d\Phi}{dt}$ | ||
| + | |||
| + | With the secondary winding short‑circuited, the voltage $ V_2 = 0$ | ||
| + | Since$ V_2 = N_2 \frac{d\Phi}{dt}$ | ||
| + | this implies that the magnetic flux $\Phi $in the core must be constant (or zero, if starting from zero initial conditions). For the net flux to be zero, the total magnetomotive force must be zero | ||
| + | |||
| + | $N_1 I_1 + N_2 I_2 = 0$ | ||
| + | |||
| + | From this, the ratio of magnitudes is : | ||
| + | |||
| + | $\boxed{\frac{I_1}{I_2} = \frac{N_2}{N_1}}$ | ||
| + | |||
| + | The negative sign indicates that the currents are in opposite phase, but the ratio of amplitudes is as given. | ||
| + | |||
| + | #### Answer | ||
| + | |||
| + | [Insert a concise answer or boxed result] | ||
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| ### Statement | |||
| $11.3.18.$ [Insert the problem statement] | |||
| ### Solution | |||
| In an ideal transformer (ideal means no losses, no leakage, and infinite magnetic permeability) | |||
| the voltage induced in each winding is proportional to the number of turns | |||
| $ V_1 = N_1 \frac{d\Phi}{dt}, V_2 = N_2 \frac{d\Phi}{dt}$ | |||
| With the secondary winding short‑circuited, the voltage $ V_2 = 0$ | |||
| Since$ V_2 = N_2 \frac{d\Phi}{dt}$ | |||
| this implies that the magnetic flux $\Phi $in the core must be constant (or zero, if starting from zero initial conditions). For the net flux to be zero, the total magnetomotive force must be zero | |||
| $N_1 I_1 + N_2 I_2 = 0$ | |||
| From this, the ratio of magnitudes is : | |||
| $\boxed{\frac{I_1}{I_2} = \frac{N_2}{N_1}}$ | |||
| The negative sign indicates that the currents are in opposite phase, but the ratio of amplitudes is as given. | |||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||