New solution

naz edited
revision #19231 newer →
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+### Statement
+
+$11.2.19.$ [Insert the problem statement]
+
+### Solution
+
+### Condition
+$11.2.19.$
+When charges are accelerated, eddy electric fields are generated, the intensity of which, if radiation is neglected, is proportional to the acceleration.
+Therefore, a charge moving with acceleration $a$ is acted upon by these electric fields by a force $F = m_{e}a$. The proportionality constant $m_{e}$ can be called the electromagnetic mass of the charge.
+a. How many times is the electromagnetic mass of a conduction electron in a long solenoid with a radius of $0.1 m$ and a number of turns per unit length of $10^3 m^{-1}$ greater than the mass of a free electron? The cross-section of the solenoid wire is $1 mm^2$, and the number of conduction electrons per unit volume of the solenoid material is $10^{23} cm^{−3}$.
+b. What parameters should the solenoid have to ensure that the electromagnetic mass of an electron in the solenoid is equal to the mass of a free electron? The number of conduction electrons per unit volume of the solenoid material is $10^{23} cm^{−3}$.
+### Solution
+a)
+First, let's define the quantities from the problem statement: $n$ is the electron concentration, $S$ is the cross-sectional area, $r$ is the radius, and $N$ is the number of turns per unit length.
+Let's assume that an alternating current $I$ flows through the solenoid, and at time $t$, its value is:
+$$I = nS\upsilon e$$
+Let's differentiate the expression with respect to time:
+$$\frac{d I}{dt} = nSae$$
+Let's assume that the field inside the solenoid is uniform and equal to:
+$$B = \mu_0 I N$$
+Differentiate with respect to time:
+$$\frac{dB}{dt} = \mu_0 nSaeN$$
+Write Faraday's law of electromagnetic induction for a current loop:
+$$E 2 \pi r = \mu_0 nSaeN \pi r^2$$
+An electric field is a force acting on a charge, or, based on the condition:
+$$E = \frac{m_e a}{e}$$
+Substitute, convert, and obtain the desired ratio:
+$$\frac{m_e}{m_{free}}=\frac{\mu_0 nS e^2Nr}{2} \approx 1.8 \cdot 10^{11}$$
+b) All that remains is to express the product of the solenoid parameters and calculate:
+$$NSr \approx 5.7 \cdot 10^{-16} m^2$$
+ Apparently, Savchenko has made a mistake
+#### Answer
+ a)
+ $$\frac{m_e}{m_{free}}=\frac{\mu_0 nS e^2Nr}{2} \approx 1.8 \cdot 10^{11}$$
+
+ б)$$NSr \approx 5.7 \cdot 10^{-16} м^2$$
+
+#### Answer
+
+[Insert a concise answer or boxed result]