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en/11.3.20.md
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| + | ### Statement | ||
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| + | $11.3.20.$ [Insert the problem statement] | ||
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| + | ### Solution | ||
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| + | The figure shows the so-called autotransformer, its feature is that the input and output windings are combined into one. | ||
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| + | The essence of the operation of such a transformer is as follows: the input voltage is applied to a fixed section of the winding, let the number of turns on it be N_1. The output voltage is removed between the common wire and terminal K, denote the number of turns between them N_2. | ||
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| + | The bottom line is that the output voltage increases proportionally as N_2 increases.: | ||
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| + | $$U = \frac{N_2}{N_1} U_0$$ | ||
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| + | Therefore, when moving the terminals to the left, the output voltage will increase. | ||
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| + | #### Answer | ||
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| + | [Insert a concise answer or boxed result] | ||
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| ### Statement | |||
| $11.3.20.$ [Insert the problem statement] | |||
| ### Solution | |||
| The figure shows the so-called autotransformer, its feature is that the input and output windings are combined into one. | |||
| The essence of the operation of such a transformer is as follows: the input voltage is applied to a fixed section of the winding, let the number of turns on it be N_1. The output voltage is removed between the common wire and terminal K, denote the number of turns between them N_2. | |||
| The bottom line is that the output voltage increases proportionally as N_2 increases.: | |||
| $$U = \frac{N_2}{N_1} U_0$$ | |||
| Therefore, when moving the terminals to the left, the output voltage will increase. | |||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||