3.5.36. a. What is the necessary forcing force for an oscillator of mass $m$ with damping coefficient $\gamma$ to begin to perform harmonic oscillations with natural frequency $\omega_0$ according to the law $x=A\cos(\omega_0t-\phi)$?
b. The amplitude of the forcing force is $F_0$, its frequency $\omega=\omega_0$. Determine the amplitude of the forced oscillations. How many times is it the deflection of the oscillator when a constant force $F_0$ is applied?
Solution
Substituting the particular (i.e. steady-state) solution $x=A\cos(\omega_0t-\phi)$ into the expression $\ddot x+2\gamma\dot x+\omega_0^2x$, we obtain $-2\gamma\omega_0A\sin(\omega_0t-\phi)$. (Note that the first and third terms cancel out, because the particular solution happens to be the solution to the homogeneous equation $\ddot x+\omega_0^2x=0$.) Thus, the required forcing is $F(t)=-2m\gamma\omega_0A\sin(\omega_0t-\phi)$.
Conversely, if the forcing has amplitude $F_0$ and $\omega=\omega_0$, then $2m\gamma\omega_0A=F_0$, and the amplitude of the forced oscillation is $A=F_0/(2m\gamma\omega_0)$. When a constant force $F_0$ is applied instead, the deflection of the oscillator is $F_0/(m\omega_0^2)$. The amplitude of the forced oscillation is thus $\omega_0/(2\gamma)$ times this deflection.
Answer
a. $F(t)=-2m\gamma\omega_0A\sin(\omega_0t-\phi)$
b. $A=F_0/(2m\gamma\omega_0)$, which is $\omega_0/(2\gamma)$ times the deflection under constant force