4.2.1 | revision #20097 | Savchenko Solutions

Statement

4.2.1. Determine the liquid pressure on the bottom surface of a floating puck of cross-section $$S$$ and mass $$m$$ , if the atmospheric pressure is $$P_0$$ .

Solution

The Archimedes force is equal to the force of gravity:

$$$F_A = mg$$$

The Archimedes force arises from the difference in pressure from different sides on the same area, therefore:

$$$(P - P_0)S = mg$$$

We get the answer:

$P = \frac{mg}{S} + P_0$

Answer

$P = \frac{mg}{S} + P_0$