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en/5.9.20.md
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| + | ### Statement | ||
| + | |||
| + | $5.9.20.$ [Insert the problem statement] | ||
| + | |||
| + | ### Solution | ||
| + | |||
| + | ### Statement | ||
| + | |||
| + | $5.9.20.$ How will the temperature in the room change if the door of a working refrigerator is left open? | ||
| + | |||
| + | ### Solution | ||
| + | |||
| + | The temperature in the room will <b>increase</b>. | ||
| + | |||
| + | A refrigerator operates on the principle of a heat pump. It absorbs an amount of heat $Q_1$ from the cooled volume and rejects an amount of heat $Q_2$ to the surroundings (via the radiator on the back). | ||
| + | To accomplish this process, the refrigerator's compressor consumes electrical energy from the grid to perform mechanical work $A$. According to the law of conservation of energy, the heat rejected into the room is: | ||
| + | $$Q_2 = Q_1 + A$$ | ||
| + | |||
| + | If the refrigerator door is left open, it begins to absorb heat $Q_1$ directly from the room air and rejects heat $Q_2$ right back into the same room. | ||
| + | The net amount of heat the room receives during each operating cycle of the refrigerator is: | ||
| + | $$\Delta Q = Q_2 - Q_1 = A$$ | ||
| + | |||
| + | Since the compressor consumes electrical energy and performs work ($A > 0$), this work is completely dissipated and converted into the internal energy of the air in the room. A refrigerator with an open door effectively acts as a standard electrical space heater with a power output equal to the power consumption of its compressor. | ||
| + | |||
| + | --- | ||
| + | P.S. However, all this only applies to boring factory models. I don't know about you, but I modified my fridge: all the exhaust heat from the compressor is dumped directly into the shower water tank. As a result, the water is always hot, no money is wasted on a water heater, and if you open the door, the fridge actually works like an air conditioner, pulling heat out of the room (it's a pity, of course, that all this is only in the palace of my dreams). | ||
| + | |||
| + | #### Answer | ||
| + | The temperature in the room will increase. | ||
| + | |||
| + | #### Answer | ||
| + | |||
| + | [Insert a concise answer or boxed result] | ||
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| ### Statement | |||
| $5.9.20.$ [Insert the problem statement] | |||
| ### Solution | |||
| ### Statement | |||
| $5.9.20.$ How will the temperature in the room change if the door of a working refrigerator is left open? | |||
| ### Solution | |||
| The temperature in the room will <b>increase</b>. | |||
| A refrigerator operates on the principle of a heat pump. It absorbs an amount of heat $Q_1$ from the cooled volume and rejects an amount of heat $Q_2$ to the surroundings (via the radiator on the back). | |||
| To accomplish this process, the refrigerator's compressor consumes electrical energy from the grid to perform mechanical work $A$. According to the law of conservation of energy, the heat rejected into the room is: | |||
| $$Q_2 = Q_1 + A$$ | |||
| If the refrigerator door is left open, it begins to absorb heat $Q_1$ directly from the room air and rejects heat $Q_2$ right back into the same room. | |||
| The net amount of heat the room receives during each operating cycle of the refrigerator is: | |||
| $$\Delta Q = Q_2 - Q_1 = A$$ | |||
| Since the compressor consumes electrical energy and performs work ($A > 0$), this work is completely dissipated and converted into the internal energy of the air in the room. A refrigerator with an open door effectively acts as a standard electrical space heater with a power output equal to the power consumption of its compressor. | |||
| --- | |||
| P.S. However, all this only applies to boring factory models. I don't know about you, but I modified my fridge: all the exhaust heat from the compressor is dumped directly into the shower water tank. As a result, the water is always hot, no money is wasted on a water heater, and if you open the door, the fridge actually works like an air conditioner, pulling heat out of the room (it's a pity, of course, that all this is only in the palace of my dreams). | |||
| #### Answer | |||
| The temperature in the room will increase. | |||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||