Added 2.2.38

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+ <meta name="description" content="A water jet boat moves in calm water. Force of water resistance to boat movement $F = k v^2$ . The speed of the ejected water relative to the boat $u$. Determine the steady-state speed of the boat, if the cross-section of the flow of water captured by the engine is $S$, the water density is $\rho$.">
+ <meta name="author" content="Aliaksandr Melnichenka">
+ <meta name="date" content="2023-10" scheme="YYYY-MM">
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+ <title>A water jet boat moves in calm water. Force of water resistance to boat movement $F = k v^2$ . The speed of the ejected water relative to the boat $u$. Determine the steady-state speed of the boat, if the cross-section of the flow of water captured by the engine is $S$, the water density is $\rho$.</title>
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+ <header style="text-align:center;">
+ <h2>Solutions of Savchenko Problems in Physics</h2>
+ <p class="author">
+ Aliaksandr Melnichenka <br/>
+ October 2023
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../#2.2">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $2.2.38.$ A water jet boat moves in calm water. Force of water resistance to boat movement $F = k v^2$ . The speed of the ejected water relative to the boat $u$. Determine the steady-state speed of the boat, if the cross-section of the flow of water captured by the engine is $S$, the water density is $\rho$.
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ </p>
+<center>
+ <figure>
+ <img src="draw.png"
+ loading="lazy" width="230" />
+ <figcaption>
+ For problem $2.2.38$
+ </figcaption>
+ </figure>
+</center>
+<p>
+
+Since in steady-state mode remains unchanged, by Newton's first law, the thrust force is compensated by the drag force
+$$F_\text{resistance}=F_\text{traction}$$
+
+During the time $dt$ the mass $dm$ of escaping water is:
+$$dm=\rho S v\,dt$$
+In this case, relative to the Non-inertial Reference Frame, the water flies out with a velocity $u-v$.
+</p><p>
+Hence the momentum $dp$ of mass $dm$
+$$dp=\rho S v(u-v)\,dt$$
+The force of water thrust, we find through the change of momentum
+$$F=\frac{dp}{dt}=\rho S v(u-v)$$
+Let's substitute and rewrite the equilibrium condition
+$$\rho S v(u-v)=k v^2$$
+From where
+$$\boxed{v=u \frac{\rho S}{\rho S+k}}$$
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $$v=\rho Su/(\rho S+k)$$
+ </p>
+
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