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<meta property="og:description" content="Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10^{-4} T. The magnetic field is perpendicular to the gravity field.">
<title>Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10^{-4} T. The magnetic field is perpendicular to the gravity field.</title>
$10.2.12.$ Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10$^{-4}$ T. The magnetic field is perpendicular to the gravity field.
</p>
<h3>Solution</h3>
<p>
Drift velocity is achieved when particle's path is unaffected respect to force fields that acting over it. So, absolute values of these forces are equal and their directions are opposed. Hence,
</p>
<p style="text-align: center;">
$mg = q~v_d~B$
</p>
<p style="text-align: center;">
$v_d = \frac{mg}{qB}$
</p>
<p>
Now, considering the following data, calculations for each particle are possible: mass of electron $m_e = 9.1 \cdot 10^{-31}$ kg, mass of proton $m_p = 1.672 \cdot 10^{-27}$ kg, absolute value of charge $q = 1.6 \cdot 10^{-19}$ C and acceleration due to gravity $g = 9.8$ m/s$^2$. Calculating,
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> astrosander01@gmail.com <br></small>
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<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="description" content="The largest dataset of solutions of 'Savchenko. Problems in Physics'. Savchenko’s Problems in General Physics is widely used to prepare for olympiads and it is a useful tool to
<meta name="description" content="Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10^{-4} T. The magnetic field is perpendicular to the gravity field.">
master and sharpen your skills and techniques in comptetitive problem solving. Some of these problems were a source
of inspiration for Jaan Kalda’s handouts and to some NBPhO problems. You may find problems from old IPhO
<meta property="og:title" content="Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10^{-4} T. The magnetic field is perpendicular to the gravity field.">
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<meta property="og:description" content="A website with solutions to physics problems from Savchenko Textbook">
<meta property="og:description" content="Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10^{-4} T. The magnetic field is perpendicular to the gravity field.">
<title>Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10^{-4} T. The magnetic field is perpendicular to the gravity field.</title>
$10.2.12.$ Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10$^{-4}$ T. The magnetic field is perpendicular to the gravity field.
$10.2.12.$ Find the drift velocity of the electron and proton in the gravity field and the Earth's magnetic field, the induction of which is equal to 0.7 · 10$^{-4}$ T. The magnetic field is perpendicular to the gravity field.
</p>
</p>
<h3>Solution</h3>
<h3>Solution</h3>
<p>
<p>
Drift velocity is achieved when particle's path is unaffected respect to force fields that acting over it. So, absolute values of these forces are equal and their directions are opposed. Hence,
Drift velocity is achieved when particle's path is unaffected respect to force fields that acting over it. So, absolute values of these forces are equal and their directions are opposed. Hence,
</p>
</p>
<p style="text-align: center;">
<p style="text-align: center;">
$mg = q~v_d~B$
$mg = q~v_d~B$
</p>
</p>
<p style="text-align: center;">
<p style="text-align: center;">
$v_d = \frac{mg}{qB}$
$v_d = \frac{mg}{qB}$
</p>
</p>
<p>
<p>
Now, considering the following data, calculations for each particle are possible: mass of electron $m_e = 9.1 \cdot 10^{-31}$ kg, mass of proton $m_p = 1.672 \cdot 10^{-27}$ kg, absolute value of charge $q = 1.6 \cdot 10^{-19}$ C and acceleration due to gravity $g = 9.8$ m/s$^2$. Calculating,
Now, considering the following data, calculations for each particle are possible: mass of electron $m_e = 9.1 \cdot 10^{-31}$ kg, mass of proton $m_p = 1.672 \cdot 10^{-27}$ kg, absolute value of charge $q = 1.6 \cdot 10^{-19}$ C and acceleration due to gravity $g = 9.8$ m/s$^2$. Calculating,
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> astrosander01@gmail.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> astrosander01@gmail.com <br></small>
