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| + | <meta name="date" content="2023-10" scheme="YYYY-MM"> | ||
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| + | <h2>Solutions of Savchenko Problems in Physics</h2> | ||
| + | <p class="author"> | ||
| + | Aliaksandr Melnichenka <br/> | ||
| + | October 2023 | ||
| + | </p> | ||
| + | </header> | ||
| + | |||
| + | <h3 id="back-link"><a href="../#1.2">$\leftarrow$Back</a></h3> | ||
| + | |||
| + | <h3> Statement </h3> | ||
| + | <p> | ||
| + | $1.2.7.$ The bus moves for $20$ seconds in a straight line to the stop, passing a distance of $310$ m. Its initial speed is $15$ $\frac{m}{s}$. Prove that the velocity of the bus changes in direction. | ||
| + | </p> | ||
| + | |||
| + | <h3>Solution</h3> | ||
| + | <p> | ||
| + | Since the bus comes to a complete stop at the end, the average speed is | ||
| + | $$v_\text{average}=\frac{15+0}{2} \frac{m}{s}=7.5 \frac{m}{s}$$ | ||
| + | If there is an equal-accelerated motion, then the body must travel a path | ||
| + | $$s = v_\text{average}\cdot t=150\text{ m}$$ | ||
| + | Whence it follows that the body has accelerated, but the motion is not equal-accelerated | ||
| + | </p> | ||
| + | |||
| + | <h4>Answer</h4> | ||
| + | <p> | ||
| + | The average velocity is greater than the initial velocity and the final velocity is zero. | ||
| + | </p> | ||
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| <meta name="author" content="Aliaksandr Melnichenka"> | |||
| <meta name="date" content="2023-10" scheme="YYYY-MM"> | |||
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| }); | |||
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| </head> | |||
| <body style=""> | |||
| <header style="text-align:center;"> | |||
| <h2>Solutions of Savchenko Problems in Physics</h2> | |||
| <p class="author"> | |||
| Aliaksandr Melnichenka <br/> | |||
| October 2023 | |||
| </p> | |||
| </header> | |||
| <h3 id="back-link"><a href="../#1.2">$\leftarrow$Back</a></h3> | |||
| <h3> Statement </h3> | |||
| <p> | |||
| $1.2.7.$ The bus moves for $20$ seconds in a straight line to the stop, passing a distance of $310$ m. Its initial speed is $15$ $\frac{m}{s}$. Prove that the velocity of the bus changes in direction. | |||
| </p> | |||
| <h3>Solution</h3> | |||
| <p> | |||
| Since the bus comes to a complete stop at the end, the average speed is | |||
| $$v_\text{average}=\frac{15+0}{2} \frac{m}{s}=7.5 \frac{m}{s}$$ | |||
| If there is an equal-accelerated motion, then the body must travel a path | |||
| $$s = v_\text{average}\cdot t=150\text{ m}$$ | |||
| Whence it follows that the body has accelerated, but the motion is not equal-accelerated | |||
| </p> | |||
| <h4>Answer</h4> | |||
| <p> | |||
| The average velocity is greater than the initial velocity and the final velocity is zero. | |||
| </p> | |||
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| <br> | |||
| <p> | |||
| <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small> | |||
| </p> | |||
| <p> | |||
| <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> astrosander01@gmail.com <br></small> | |||
| </p> | |||
| </footer> | |||
| </body> | |||
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