Added alternative solution to 3.2.3 3.2.4 3.2.6 3.2.7 3.2.8 3.2.9 3.2.10 3.2.11 3.2.12 3.2.13 3.2.14 3.2.18 3.2.19 3.2.20 3.2.21 3.2.22 3.2.23 3.2.24 3.2.25 3.2.28 3.2.29 3.2.31

astrosander edited
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revision #421 parent #382 GitHub fbdf260 ← older newer →
ru/3.2.29.md +8 −0
@@ -178,6 +178,14 @@
$T=2\pi\sqrt{\frac{m}{k^*}}=2\pi\sqrt{\frac{m}{2k}}$<br><br>
а) $t_1=\frac{T}{4}=\frac{\pi}{2}\sqrt{\frac{m}{2k}}$<br><br>
б) $t_2=\frac{3}{4}T=\frac{3}{2}\pi\sqrt{\frac{m}{2k}}$<br><br>
+
+ <hr>
+ <h3>
+ Альтернативное решение:
+ </h3>
+ <div class="solutions">
+ <img class="ScreenS" src="01.jpg">
+ </div>
<h3>
Ответ: $t_1=\frac{\pi}{2}\sqrt{\frac{m}{2k}}$, $t_2=\frac{3}{2}\pi\sqrt{\frac{m}{2k}}$.
<h3>
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