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| <h2>Solutions of Savchenko Problems in Physics</h2> | | <h2>Solutions of Savchenko Problems in Physics</h2> |
| <p class="author"> | | <p class="author"> |
| Aliaksandr Melnichenka <br/> | | Aliaksandr Melnichenka <br/> |
| October 2023 | | October 2023 |
| </p> | | </p> |
| </header> | | </header> |
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| <h3 id="back-link"><a href="../../#1.4">$\leftarrow$Back</a></h3> | | <h3 id="back-link"><a href="../../#1.4">$\leftarrow$Back</a></h3> |
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| <h3> Statement </h3> | | <h3> Statement </h3> |
| <p> | | <p> |
| $1.4.17.$ It is raining heavily. Drop rate $u$. The ball slides on the asphalt at a speed of $v$. How many times in the same period of time does it get more drops than the same, but stationary ball? Does the answer change if the ball is not round? | | $1.4.17.$ It is raining heavily. Drop rate $u$. The ball slides on the asphalt at a speed of $v$. How many times in the same period of time does it get more drops than the same, but stationary ball? Does the answer change if the ball is not round? |
| </p> | | </p> |
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| <h3>Solution</h3> | | <h3>Solution</h3> |
| <p> | | <p> |
| <p>During time $t$, all the drops that are in a cylinder of height $ut$ and base area $S_1$ equal to the area of the central cross-section of the ball perpendicular to $u$ fall on a stationary ball. That is, in the first case</p> | | <p>During time $t$, all the drops that are in a cylinder of height $ut$ and base area $S_1$ equal to the area of the central cross-section of the ball perpendicular to $u$ fall on a stationary ball. That is, in the first case</p> |
| <p class="exp">$$N_1 = utS_1$$</p> | | <p class="exp">$$N_1 = utS_1$$</p> |
| <p>In the second case, we move to the reference frame of a rolling ball, then the drops fall on it with a speed of </p> | | <p>In the second case, we move to the reference frame of a rolling ball, then the drops fall on it with a speed of </p> |
| <p class="exp">$$u_1 = \sqrt{u^2 + v^2}$$</p> | | <p class="exp">$$u_1 = \sqrt{u^2 + v^2}$$</p> |
| <p class="exp">$$N_2 = u_1 t S_2$$</p> | | <p class="exp">$$N_2 = u_1 t S_2$$</p> |
| <p>where $S_2$ is equal to the area of the central cross-section of the ball perpendicular to $u_1$. For a ball-ball $S_1 = S_2 = S$, and then</p> | | <p>where $S_2$ is equal to the area of the central cross-section of the ball perpendicular to $u_1$. For a ball-ball $S_1 = S_2 = S$, and then</p> |
| <p class="exp">$$N_2 = \sqrt{u^2 + v^2} t S$$</p> | | <p class="exp">$$N_2 = \sqrt{u^2 + v^2} t S$$</p> |
| <p>Where we get the desired ratio</p> | | <p>Where we get the desired ratio</p> |
| <p class="exp"> | | <p class="exp"> |
| $$ \fbox{$\dfrac{N_2}{N_1} = \sqrt{1 + \dfrac{v^2}{u^2}}$} $$ | | $$ \fbox{$\dfrac{N_2}{N_1} = \sqrt{1 + \dfrac{v^2}{u^2}}$} $$ |
| </p> | | </p> |
| <p>When the ball has a shape different from a sphere, its cross-sectional area will vary from the plane of the section </p> | | <p>When the ball has a shape different from a sphere, its cross-sectional area will vary from the plane of the section </p> |
| <p class="exp">$$S_1\neq S_2\neq S$$</p> | | <p class="exp">$$S_1\neq S_2\neq S$$</p> |
| <p>Thus, the answer obtained will also vary depending on the shape of the ball </p> | | <p>Thus, the answer obtained will also vary depending on the shape of the ball </p> |
| <p >NO: For additional reading, I recommend the discussion of this problem on <a href="https://ask.bc-pf.org/t/zadacha-pro-dozhd-i-myach-zadachnik-1001/3855" target="_blank">ask.bc-pf.org</a> </p> | | <p >NO: For additional reading, I recommend the discussion of this problem on <a href="https://ask.bc-pf.org/t/zadacha-pro-dozhd-i-myach-zadachnik-1001/3855" target="_blank">ask.bc-pf.org</a> </p> |
| </p> | | </p> |
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| <h4>Answer</h4> | | <h4>Answer</h4> |
| <p> | | <p> |
| <p>More drops fall on a rolling ball in $\dfrac{N_2}{N_1} = \sqrt{1 + \dfrac{v^2}{u^2}}$ times.</p> | | <p>More drops fall on a rolling ball in $\dfrac{N_2}{N_1} = \sqrt{1 + \dfrac{v^2}{u^2}}$ times.</p> |
| </p> | | </p> |
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