Translated 2.1.13-2.1.33

astrosander edited
revision #6362 GitHub 6dccb13 newer →
@@ -0,0 +1,95 @@
+<!DOCTYPE html>
+<html lang="en">
+
+<head>
+ <meta charset="utf-8">
+ <meta name="viewport" content="width=device-width, initial-scale=1.0">
+ <meta http-equiv="content-language" content="en">
+ <meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
+ <meta name="description" content="A car with a powerful engine, starting from a place, gains a speed of 72 \frac{km}{h} in 5 seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?">
+ <meta name="author" content="Aliaksandr Melnichenka">
+ <meta name="date" content="2023-10" scheme="YYYY-MM">
+ <meta property="og:title" content="A car with a powerful engine, starting from a place, gains a speed of 72 \frac{km}{h} in 5 seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?">
+ <meta property="og:image" content="img/logo.png">
+ <meta property="og:description" content="A car with a powerful engine, starting from a place, gains a speed of 72 \frac{km}{h} in 5 seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?">
+ <meta name="yandex-verification" content="6cfda41f74038368">
+ <title>A car with a powerful engine, starting from a place, gains a speed of 72 \frac{km}{h} in 5 seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?</title>
+ <link rel="stylesheet" href="https://savchenkosolutions.com/css/css-latex/style.css">
+ <link rel="icon" href="https://savchenkosolutions.com/img/logo.png" type="image/png">
+ <script src="https://savchenkosolutions.com/js/jquery-1.10.1.min.js"></script>
+ <script async src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.7/MathJax.js?config=TeX-MML-AM_CHTML"></script>
+ <script type="text/x-mathjax-config">
+ MathJax.Hub.Config({
+ extensions: ['tex2jax.js'],
+ jax: ['input/TeX', 'output/HTML-CSS'],
+ tex2jax: {
+ inlineMath: [['$', '$'], ['$', '$']],
+ processEscapes: true,
+ processClass: 'tex2jax',
+ ignoreClass: 'html'
+ },
+ showProcessingMessages: false,
+ messageStyle: 'none'
+ });
+ </script>
+</head>
+ <body style="">
+ <header style="text-align:center;">
+ <h2>Solutions of Savchenko Problems in Physics</h2>
+ <p class="author">
+ Aliaksandr Melnichenka <br/>
+ October 2023
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $2.1.29.$ A car with a powerful engine, starting from a place, gains a speed of $72$ $\frac{km}{h}$ in $5$ seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ a<center>
+<figure>
+<img src="https://savchenkosolutions.com/2/2.1.29/sol.jpg"
+loading="lazy" width="350" />
+<figcaption>
+Forces acting on the car
+</figcaption>
+</figure>
+</center>
+
+<p>
+Finding the deceleration value
+$$ a = -\frac{\Delta v}{\Delta t} = -4 \,\frac{m}{s} $$
+
+$$ \Delta t = \frac{\Delta v}{a} $$
+2. The kinematic equations of motion in this case are represented as follows:
+$$ \boxed{x=v_0t-\frac{v \Delta t^2}{2}=\frac{v_0^2}{2a}=50 \,m} $$
+Let's find the coefficient of friction $\mu $:
+$$ ma = \mu mg $$
+
+$$ \boxed{\mu = \frac{a}{g} = 0.4} $$
+</p>
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $$\mu ≈ 0.4\text{; }l ≈ 50 \text{ m}$$
+ </p>
+
+
+ <footer class="row container">
+ <br>
+ <p>
+ <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small>
+ </p>
+ <p>
+ <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
+ </p>
+ </footer>
+ </body>
+
+</html>