Updated 2.2.39, 2.3.45-46,2.6.37,2.6.41

astrosander edited
revision #6383 parent #6374 GitHub 1ee7785 ← older newer →
@@ -87,8 +87,8 @@
Now, let's consider circular motion:</p><p>
Given the centripetal acceleration $a=\frac{u^2}{R_0}$, the presence of rotational motion of which causes centrifugal force, compensating gravitational force, in the equilibrium condition.
$$\frac{mu^2}{R_0}=\frac{GmM}{R_0^2} \Leftrightarrow \frac{GM}{R_0}=u^2$$
−Substituting into the final formulae of motion
−$$\frac{1}{2}v^2=u^2\left(1+\frac{R_0}{R_\text{1max}}\right)$$
+Substituting into the final formula of motion
+$$\frac{1}{2}v^2=u^2\left(1-\frac{R_0}{R_\text{1max}}\right)$$
$$\frac{1}{2}v^2\left(1+\frac{R_0}{R_\text{2max}}\right)=u^2$$
Transforming the obtained expressions
$$R_0=R_\text{1max}\cdot\left(1-\frac{1}{2}\frac{v^2}{u^2}\right)=R_\text{2max}\cdot\left(2\frac{u^2}{v^2}-1\right)$$
unchanged lines 26