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<title>A ball flies into a tube of length l, inclined at an angle \alpha to the horizon, with a horizontal velocity v. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.</title>
$1.3.16^*.$ A ball flies into a tube of length $l$, inclined at an angle $\alpha$ to the horizon, with a horizontal velocity $v$. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.
$\begin{aligned}&t=\frac{2v}{g}\operatorname{ctg}\alpha\text{ with }v\cos\alpha<\sqrt{2gl\sin\alpha};\\&t=\frac vg\operatorname{ctg}\alpha\bigg(1-\sqrt{1-\frac{2gl\operatorname{tg}\alpha}{v^2\cos\alpha}}\bigg)\text{ with }v\cos\alpha>\sqrt{2gl\sin\alpha}.\end{aligned}$
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<meta name="description" content="A ball flies into a tube of length l, inclined at an angle \alpha to the horizon, with a horizontal velocity v. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.">
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<meta property="og:description" content="A ball flies into a tube of length l, inclined at an angle \alpha to the horizon, with a horizontal velocity v. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.">
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<title>A ball flies into a tube of length l, inclined at an angle \alpha to the horizon, with a horizontal velocity v. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.</title>
<title>A ball flies into a tube of length l, inclined at an angle \alpha to the horizon, with a horizontal velocity v. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.</title>
$1.3.16^*.$ A ball flies into a tube of length $l$, inclined at an angle $\alpha$ to the horizon, with a horizontal velocity $v$. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.
$1.3.16^*.$ A ball flies into a tube of length $l$, inclined at an angle $\alpha$ to the horizon, with a horizontal velocity $v$. Determine the time of the ball's stay in the pipe, if the ball hits its walls elastic.
$\begin{aligned}&t=\frac{2v}{g}\operatorname{ctg}\alpha\text{ with }v\cos\alpha<\sqrt{2gl\sin\alpha};\\&t=\frac vg\operatorname{ctg}\alpha\bigg(1-\sqrt{1-\frac{2gl\operatorname{tg}\alpha}{v^2\cos\alpha}}\bigg)\text{ with }v\cos\alpha>\sqrt{2gl\sin\alpha}.\end{aligned}$
$\begin{aligned}&t=\frac{2v}{g}\operatorname{ctg}\alpha\text{ with }v\cos\alpha<\sqrt{2gl\sin\alpha};\\&t=\frac vg\operatorname{ctg}\alpha\bigg(1-\sqrt{1-\frac{2gl\operatorname{tg}\alpha}{v^2\cos\alpha}}\bigg)\text{ with }v\cos\alpha>\sqrt{2gl\sin\alpha}.\end{aligned}$
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
