<p>Since the thread is rigid and inextensible, its length is preserved during the movement of the loads.</p>
<p>Let load $B$ rise a distance equal to $L$ in time $\Delta t$, then load $A$ will fall a distance $\frac{L}{2}$ in the same time.</p>
<p>This follows from the fact that on both sides of block $1$ the thread will lengthen by $\frac{L}{2}$, which means that the center of the block will fall the same distance. In this case, the length of the thread is preserved.</p>
<p>Then on one side</p>
<p class="exp">$$L = v_B \cdot\Delta t$$</p>
<p>and on the other</p>
<p class="exp">
$$\frac{L}{2} = v_A \cdot\Delta t $$
</p>
<p>Therefore,</p>
<p class="exp">$$v_B \cdot\Delta t = 2v_A \cdot\Delta t$$</p>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<p>Since the thread is rigid and inextensible, its length is preserved during the movement of the loads.</p>
<p>Since the thread is rigid and inextensible, its length is preserved during the movement of the loads.</p>
<p>Let load $B$ rise a distance equal to $L$ in time $\Delta t$, then load $A$ will fall a distance $\frac{L}{2}$ in the same time.</p>
<p>Let load $B$ rise a distance equal to $L$ in time $\Delta t$, then load $A$ will fall a distance $\frac{L}{2}$ in the same time.</p>
<p>This follows from the fact that on both sides of block $1$ the thread will lengthen by $\frac{L}{2}$, which means that the center of the block will fall the same distance. In this case, the length of the thread is preserved.</p>
<p>This follows from the fact that on both sides of block $1$ the thread will lengthen by $\frac{L}{2}$, which means that the center of the block will fall the same distance. In this case, the length of the thread is preserved.</p>
<p>Then on one side</p>
<p>Then on one side</p>
<p class="exp">$$L = v_B \cdot\Delta t$$</p>
<p class="exp">$$L = v_B \cdot\Delta t$$</p>
<p>and on the other</p>
<p>and on the other</p>
<p class="exp">
<p class="exp">
$$\frac{L}{2} = v_A \cdot\Delta t $$
$$\frac{L}{2} = v_A \cdot\Delta t $$
</p>
</p>
<p>Therefore,</p>
<p>Therefore,</p>
<p class="exp">$$v_B \cdot\Delta t = 2v_A \cdot\Delta t$$</p>
<p class="exp">$$v_B \cdot\Delta t = 2v_A \cdot\Delta t$$</p>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
