Updated greek laters @ latex compiling

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revision #9872 parent #9498 GitHub dbb31ba ← older newer →
en/1.3.22.md +5 −5
@@ -71,23 +71,23 @@
<p>Along the $Oy$ axis, the second plane must shift by the value of the double radius-curvature of the turn trajectory, and the first plane must shift in time $t$ by the value $vt$ along the $Ox$ axis.</p>
<p>Let's write the condition for losing sight of each other</p>
<p class="exp">
−$$ (2r)^2 + (l-vt)^2 = l^2\;(1)$$
+$$ (2r)^2 + (l-vt)^2 = l^2\quad(1)$$
</p>
<p>Since the speed remains unchanged $v = \text{сonst}$</p>
<p class="exp">
−$$ vt = \pi r\;(2)$$
+$$ vt = \pi r\quad(2)$$
</p>
<p>Substitute $(2)$ into $(1)$</p>
<p class="exp">
−$$ (4+\pi^2)r^2 - 2l \pi r = 0\;(3)$$
+$$ (4+\pi^2)r^2 - 2l \pi r = 0\quad(3)$$
</p>
<p>Express $r$</p>
<p class="exp">
−$$ r = l \frac{2 \pi}{4+\pi^2}\;(4) $$
+$$ r = l \frac{2 \pi}{4+\pi^2}\quad(4) $$
</p>
<p>Then, the acceleration with which the second plane is moving</p>
<p class="exp">
−$$ a = \frac{v^2}{r} = \frac{v^2}{l} \frac{4+\pi^2}{2 \pi}\;(5) $$
+$$ a = \frac{v^2}{r} = \frac{v^2}{l} \frac{4+\pi^2}{2 \pi}\quad(5) $$
</p>
</p>
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