Updated greek laters @ latex compiling

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правка #10054 предыдущая #9396 GitHub dbb31ba ← раньше позже →
en/2.1.22.md +2 −2
@@ -84,11 +84,11 @@
$$ a = g( \sin \alpha - \mu \cos \alpha ) $$
The speed will become equal to $v_0$ only at the end of the descent, because the law of conservation of energy has not been repealed, therefore
−$$ \frac{dv}{dt} = g( \sin \alpha + \mu \cos \alpha ) $$
+$$ \frac{dv}{dt} = g( \sin \alpha + \mu \cos \alpha ) $$
$$ \int_{0}^{v_{0} } dv = g( \sin \alpha + \mu \cos \alpha ) = \int_{0}^{t_{2} } dt $$
−$$ t_{2} = \frac{v_{0} }{g ( \sin \alpha + \mu \cos \alpha ) } $$
+$$ t_{2} = \frac{v_{0} }{g ( \sin \alpha + \mu \cos \alpha ) } $$
The required time will be determined as the sum $t = t_{1} + t_{2}$
$$ \boxed{t = \frac{2v_{0} \sin \alpha }{g( \sin^{2} \alpha - \mu^{2} \cos^{2} \alpha )}} $$
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