Updated greek laters @ latex compiling

astrosander правка от
правка #10084 предыдущая #9288 GitHub dbb31ba ← раньше
@@ -71,11 +71,11 @@
From Momentum Conservation Law (MCL)
$$(m_1+m_2+m_3)~\vec{V} = m_1\vec{v_1}+m_2\vec{v_2}+m_3\vec{v_3}$$
Since velocity's vectors are mutually perpendicular, their directions can be fundamental for establishing the spatial coordinated system. So, let be $\hat{v_1}$, $\hat{v_2}$ and $\hat{v_3}$ the unitary vectors for each direction. Applying MCL for each direction,
− $$(m_1+m_2+m_3)V_1 = m_1v_1 \;(1)$$
− $$(m_1+m_2+m_3)V_2 = m_2v_2 \;(2)$$
− $$(m_1+m_2+m_3)V_3 = m_3v_3 \;(3)$$
+ $$(m_1+m_2+m_3)V_1 = m_1v_1 \quad(1)$$
+ $$(m_1+m_2+m_3)V_2 = m_2v_2 \quad(2)$$
+ $$(m_1+m_2+m_3)V_3 = m_3v_3 \quad(3)$$
where $V_1$, $V_2$ and $V_3$ are the components of velocity $\vec{V}$,
− $$V=\sqrt{V_1^2+V_2^2+V_3^2} \;(4)$$
+ $$V=\sqrt{V_1^2+V_2^2+V_3^2} \quad(4)$$
Substituting $(1)$, $(2)$ and $(3)$ into $(4)$
$$\boxed{V=\frac{\sqrt{m_1^2v_1^2+m_2^2v_2^2+m_3^2v_3^2}}{m_1+m_2+m_3}}$$
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