Updated spacing between @ latex expressions

astrosander правка от 6 окт. 2024 г., 00:48

правка #10320 предыдущая #10060 GitHub c702ebe ← раньше позже →

en/2.1.29.md +3 −3

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			<h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3>

			<h3> Statement </h3>
			<p>
			$2.1.29.$ A car with a powerful engine, starting from a place, gains a speed of $72$ $\frac{km}{h}$ in $5$ seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?
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			<h3>Solution</h3>
			<p>
			a<center>
			<figure>
			<img src="https://savchenkosolutions.com/2/2.1.29/sol.jpg"
			loading="lazy" width="350" />
			<figcaption>
			Forces acting on the car
			</figcaption>
			</figure>
			</center>

			<p>
			Finding the deceleration value
			$$ a = -\frac{\Delta v}{\Delta t} = -4 \,\frac{m}{s} $$

		@@ -72,16 +72,16 @@
			$$ \Delta t = \frac{\Delta v}{a} $$
			2. The kinematic equations of motion in this case are represented as follows:
			$$ \boxed{x=v_0t-\frac{v \Delta t^2}{2}=\frac{v_0^2}{2a}=50 \,m} $$
		−	Let's find the coefficient of friction $\mu $:
		+	Let's find the coefficient of friction $\mu$:
			$$ ma = \mu mg $$

		−	$$ \boxed{\mu = \frac{a}{g} = 0.4} $$
		+	$$ \boxed{\mu = \frac{a}{g} = 0.4} $$
			</p>
			</p>

			<h4>Answer</h4>
			<p>
		−	$$\mu \approx 0.4\text{; }l \approx 50 \text{ m}$$
		+	$$\mu\approx 0.4\text{; }l \approx 50 \text{ m}$$
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	<i><b>knowledge must be free</b></i>		<i><b>knowledge must be free</b></i>
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	<h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3>		<h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3>

	<h3> Statement </h3>		<h3> Statement </h3>
	<p>		<p>
	$2.1.29.$ A car with a powerful engine, starting from a place, gains a speed of $72$ $\frac{km}{h}$ in $5$ seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?		$2.1.29.$ A car with a powerful engine, starting from a place, gains a speed of $72$ $\frac{km}{h}$ in $5$ seconds. Find the coefficient of friction between the wheels and the road. What is the shortest braking distance of a car that has reached this speed?
	</p>		</p>

	<h3>Solution</h3>		<h3>Solution</h3>
	<p>		<p>
	a<center>		a<center>
	<figure>		<figure>
	<img src="https://savchenkosolutions.com/2/2.1.29/sol.jpg"		<img src="https://savchenkosolutions.com/2/2.1.29/sol.jpg"
	loading="lazy" width="350" />		loading="lazy" width="350" />
	<figcaption>		<figcaption>
	Forces acting on the car		Forces acting on the car
	</figcaption>		</figcaption>
	</figure>		</figure>
	</center>		</center>

	<p>		<p>
	Finding the deceleration value		Finding the deceleration value
	$$ a = -\frac{\Delta v}{\Delta t} = -4 \,\frac{m}{s} $$		$$ a = -\frac{\Delta v}{\Delta t} = -4 \,\frac{m}{s} $$

	@@ -72,16 +72,16 @@
	$$ \Delta t = \frac{\Delta v}{a} $$		$$ \Delta t = \frac{\Delta v}{a} $$
	2. The kinematic equations of motion in this case are represented as follows:		2. The kinematic equations of motion in this case are represented as follows:
	$$ \boxed{x=v_0t-\frac{v \Delta t^2}{2}=\frac{v_0^2}{2a}=50 \,m} $$		$$ \boxed{x=v_0t-\frac{v \Delta t^2}{2}=\frac{v_0^2}{2a}=50 \,m} $$
	Let's find the coefficient of friction $\mu $:		Let's find the coefficient of friction $\mu$:
	$$ ma = \mu mg $$		$$ ma = \mu mg $$

	$$ \boxed{\mu = \frac{a}{g} = 0.4} $$		$$ \boxed{\mu = \frac{a}{g} = 0.4} $$
	</p>		</p>
	</p>		</p>

	<h4>Answer</h4>		<h4>Answer</h4>
	<p>		<p>
	$$\mu \approx 0.4\text{; }l \approx 50 \text{ m}$$		$$\mu\approx 0.4\text{; }l \approx 50 \text{ m}$$
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