Updated spacing between @ latex expressions

astrosander правка от
Посмотреть решение История
правка #10346 предыдущая #10070 GitHub c702ebe ← раньше позже →
en/2.1.37.md +4 −4
@@ -70,13 +70,13 @@
</p>
<p>
Let's write the equation after a long period of time:
−$$ mg=A\rho _0r^2v^2\quad(1) $$
+$$ mg=A\rho_0r^2v^2\quad(1) $$
Let's find $m$ through the volume $V$:
−$$ m=\rho V=\frac{4}{3} \rho \pi r^3 $$
+$$ m=\rho V=\frac{4}{3} \rho\pi r^3 $$
And we substitute into $(1)$:
−$$ \frac{4}{3} \rho \pi r^3 g=A\rho _0r^2v^2 $$
+$$ \frac{4}{3} \rho\pi r^3 g=A\rho_0r^2v^2 $$
From here:
−$$ \boxed{v = \sqrt{\frac{4}{3} \rho \pi r g \cdot \frac{1}{A\rho _0}}\approx 5.5\,\frac{\text{m}}{\text{s}}\quad(2)} $$
+$$ \boxed{v = \sqrt{\frac{4}{3} \rho\pi r g \cdot \frac{1}{A\rho_0}}\approx 5.5\,\frac{\text{m}}{\text{s}}\quad(2)} $$
From $(2)$, the larger $r$, the larger $v$. This means that larger drops fall
to the ground at a higher speed
</p>
ещё строк без изменений 20