Fixed epsilon appearance @ 7.1.17, 7.1.22

astrosander правка от
правка #11388 предыдущая #10190 GitHub 4658b79 ← раньше
@@ -92,9 +92,9 @@
$$T = \frac{2R}{v-v_Q\left(1+\frac{M}{m}\right)} \quad(9)$$
Putting $(8)$ into $(9)$
$$T = \frac{2MR}{\mp\sqrt{M^2v^2-2M\left(1+\frac{M}{m}\right)\frac{kQq}{R}}}$$
− Choosing ``plus'' (+) sign, because time is non-negative, taking $k = 1/(4\pi\epsilon_0)$ and developing
− $$\boxed{T = \frac{2R}{v}\left[1-\frac{qQ(M+m)}{2\pi\epsilon_0mMv^2}\right]^{-\frac{1}{2}}}$$
− This is valid for $\frac{\mu v^2}{2}>\frac{qQ}{4\pi\epsilon_0R}$, where $\mu = \frac{mM}{M+m}$ is the reduced mass.
+ Choosing ``plus'' (+) sign, because time is non-negative, taking $k = 1/(4\pi\varepsilon_0)$ and developing
+ $$\boxed{T = \frac{2R}{v}\left[1-\frac{qQ(M+m)}{2\pi\varepsilon_0mMv^2}\right]^{-\frac{1}{2}}}$$
+ This is valid for $\frac{\mu v^2}{2}>\frac{qQ}{4\pi\varepsilon_0R}$, where $\mu = \frac{mM}{M+m}$ is the reduced mass.
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