A charge of 1 C moving at a speed of 1 \text{ m/s} in a magnetic field is acted upon by a force of 10 N. The charge moves at an angle of 30^{\circ} to the direction of the magnetic field induction. What is the induction of this field?

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    <h3 id="back-link"><a href="/#9.1">$\leftarrow$Back</a></h3>

    <h3> Statement </h3>
    <p>
        $9.1.2.$ A charge of $1$ C moving at a speed of $1 \text{ m/s}$ in a magnetic field is acted upon by a force of $10$ N. The charge moves at an angle of $30^{\circ}$ to the direction of the magnetic field induction. What is the induction of this field?
    </p>

    <h3>Solution</h3>
    <p>
        Lorentz force acting on a moving particle in a magnetic field

$$\vec{F} = q(\vec{v}\times \vec{B})$$
rewriting in scalar form we get
$$F = qvB\sin\alpha$$
where $\alpha$ is the angle between $\vec{B}$ and $\vec{v}$

Substituting the values ​​from the condition, we get
$$\boxed{{B} = \frac{F}{qv \sin\alpha} = 20 \text{ T}}$$

    <h4>Answer</h4>
    <p>
        $${B} = \frac{F}{qv \sin\alpha} = 20 \text{ T}$$
    </p>
	<p style="text-align: right; font-style: italic; font-size: 14;">
      Andrei Yersh<br>
    </p>


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