A force of 15 N acts on a linear conductor of length 10 cm, located perpendicular to a magnetic field, if the current in the conductor is 1.5 A. Find the induction of the magnetic field.

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Solutions of Savchenko Problems in Physics
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    <h3 id="back-link"><a href="/#9.1">$\leftarrow$Back</a></h3>

    <h3> Statement </h3>
    <p>
        $9.1.1.$ A force of 15 N acts on a linear conductor of length $10$ cm, located perpendicular to a magnetic field, if the current in the conductor is $1.5$ A. Find the induction of the magnetic field.
    </p>

    <h3>Solution</h3>
    <p>
        We find the Ampere force as

$$\vec{F} = (\vec{Il})\times \vec{B}$$
In scalar form, this expression can be rewritten as
$$F = B\cdot Il \cdot \sin\alpha\quad(1)$$
since the field is perpendicular to the current element, then
$$\alpha =90^{\circ};\quad \sin\alpha =1$$
From here, we rewrite the expression $(1)$ as
$$F = B \cdot Il \Rightarrow \boxed{B = \frac{F}{Il} = 100\text{ T}}$$

    </p>

    <h4>Answer</h4>
    <p>
        $$B = \frac{F}{Il} = 100\text{ T}$$
    </p>
	<p style="text-align: right; font-style: italic; font-size: 14;">
      Andrei Yersh<br>
    </p>


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