Правка раздела «Solution»
en/7.1.3.md
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| ### Statement | |||
| $7.1.3$ A particle with a charge $q$ and a mass $m$ passes through a region of a uniform electric field of length $d$ in time $t$. The velocity $v$ of a particle entering the field is directed along the field. Determine the electric field intensity. | |||
| @@ -4,4 +4,4 @@Statement | |||
| ### Solution | |||
| − | The motion of particle is accelerated by electric field, so $$d = vt-\frac{at^2}{2} | ||
| + | The motion of particle is accelerated by electric field, so $$d = vt-\frac{at^2}{2} \tag{1}$$ Applying Newton Second Law $$F = qE = ma$$ then, $$a = \frac{qE}{m} \tag{2}$$ Putting $(2)$ into $(1)$ $$\boxed{E = 2m\frac{d-vt}{qt^2}}$$ | ||
| ### Statement | ### Statement | ||
| $7.1.3$ A particle with a charge $q$ and a mass $m$ passes through a region of a uniform electric field of length $d$ in time $t$. The velocity $v$ of a particle entering the field is directed along the field. Determine the electric field intensity. | $7.1.3$ A particle with a charge $q$ and a mass $m$ passes through a region of a uniform electric field of length $d$ in time $t$. The velocity $v$ of a particle entering the field is directed along the field. Determine the electric field intensity. | ||
| @@ -4,4 +4,4 @@Statement | |||
| ### Solution | ### Solution | ||
| The motion of particle is accelerated by electric field, so $$d = vt-\frac{at^2}{2} |
The motion of particle is accelerated by electric field, so $$d = vt-\frac{at^2}{2} \tag{1}$$ Applying Newton Second Law $$F = qE = ma$$ then, $$a = \frac{qE}{m} \tag{2}$$ Putting $(2)$ into $(1)$ $$\boxed{E = 2m\frac{d-vt}{qt^2}}$$ | ||