Правка раздела «Answer»
en/14.1.1.md
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| − | ### Statement | ||
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| − | $14.1.1.$ [Insert the problem statement] | ||
| − | |||
| − | ### Solution | ||
| − | |||
| ### Problem | |||
| $14.1.1.$ A radio signal reflected from an airplane returned to the radar after \(10^{-4}\) seconds. How far was the airplane from the radar at the moment the signal was reflected? | |||
| ### Solution | |||
| If the airplane is at a distance \(l\) from the radar, the radio signal travels this distance twice – first from the radar to the airplane, and then back. The speed of the radio signal is equal to the speed of light. | |||
| \[ | |||
| 2l = c \cdot t | |||
| \] | |||
| \[ | |||
| l = \frac{c \cdot t}{2} | |||
| \] | |||
| Substituting the values, we get: | |||
| \(l = 15\) km. | |||
| @@ -26,7 +20,3 @@Solution | |||
| #### Answer | |||
| \(l = 15\) km. | |||
| − | |||
| − | #### Answer | ||
| − | |||
| − | [Insert a concise answer or boxed result] | ||
| @@ -1,9 +1,3 @@ | |||
| ### Statement | |||
| $14.1.1.$ [Insert the problem statement] | |||
| ### Solution | |||
| ### Problem | ### Problem | ||
| $14.1.1.$ A radio signal reflected from an airplane returned to the radar after \(10^{-4}\) seconds. How far was the airplane from the radar at the moment the signal was reflected? | $14.1.1.$ A radio signal reflected from an airplane returned to the radar after \(10^{-4}\) seconds. How far was the airplane from the radar at the moment the signal was reflected? | ||
| ### Solution | ### Solution | ||
| If the airplane is at a distance \(l\) from the radar, the radio signal travels this distance twice – first from the radar to the airplane, and then back. The speed of the radio signal is equal to the speed of light. | If the airplane is at a distance \(l\) from the radar, the radio signal travels this distance twice – first from the radar to the airplane, and then back. The speed of the radio signal is equal to the speed of light. | ||
| \[ | \[ | ||
| 2l = c \cdot t | 2l = c \cdot t | ||
| \] | \] | ||
| \[ | \[ | ||
| l = \frac{c \cdot t}{2} | l = \frac{c \cdot t}{2} | ||
| \] | \] | ||
| Substituting the values, we get: | Substituting the values, we get: | ||
| \(l = 15\) km. | \(l = 15\) km. | ||
| @@ -26,7 +20,3 @@Solution | |||
| #### Answer | #### Answer | ||
| \(l = 15\) km. | \(l = 15\) km. | ||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||