Новое решение

Arman правка от 23 апр. 2026 г., 14:04

правка #17951 позже →

en/12.1.6.md +51 −0

		@@ -0,0 +1,51 @@
		+	### Statement
		+
		+	$12.1.6.$ [Insert the problem statement]
		+
		+	### Solution
		+
		+
		+	Let $ab=L$.By applying the law of electromagnetic induction to the countour $baa'b'$ we get:
		+
		+
		+
		+	\begin{equation}
		+	E L=\frac{d\Phi}{dt}
		+	\end{equation}
		+
		+
		+
		+	In time $dt$ the wave moves a distance $cdt$.So the change of the magnetic flux is:
		+
		+	\begin{equation}
		+	d\Phi=BLcdt
		+	\end{equation}
		+
		+
		+
		+	By plugging eq(2) into the first we find that(in SI units):
		+
		+
		+	\begin{equation}
		+	B=\frac{E}{c}
		+	\end{equation}
		+
		+
		+
		+	In Gaussian units Faraday's law for the same countour looks like:
		+
		+	\begin{equation}
		+	EL=\frac{1}{c}\frac{d\Phi}{dt}
		+	\end{equation}
		+
		+
		+
		+	So the answer in CGS units is:
		+
		+	\begin{equation}
		+	B=E
		+	\end{equation}
		+
		+	#### Answer
		+
		+	[Insert a concise answer or boxed result]

	@@ -0,0 +1,51 @@
			### Statement

			$12.1.6.$ [Insert the problem statement]

			### Solution


			Let $ab=L$.By applying the law of electromagnetic induction to the countour $baa'b'$ we get:



			\begin{equation}
			E L=\frac{d\Phi}{dt}
			\end{equation}



			In time $dt$ the wave moves a distance $cdt$.So the change of the magnetic flux is:

			\begin{equation}
			d\Phi=BLcdt
			\end{equation}



			By plugging eq(2) into the first we find that(in SI units):


			\begin{equation}
			B=\frac{E}{c}
			\end{equation}



			In Gaussian units Faraday's law for the same countour looks like:

			\begin{equation}
			EL=\frac{1}{c}\frac{d\Phi}{dt}
			\end{equation}



			So the answer in CGS units is:

			\begin{equation}
			B=E
			\end{equation}

			#### Answer

			[Insert a concise answer or boxed result]