Новое решение
en/9.3.6.md
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| + | ### Statement | ||
| + | |||
| + | $9.3.6.$ [Insert the problem statement] | ||
| + | |||
| + | ### Solution | ||
| + | |||
| + | а)Energy density (magnetic pressure) is calculated using the formula $$P=w=\frac{B^2}{2\mu_0}$$ | ||
| + | Considering the induction to be constant throughout the entire cross-section and equal to $B=\frac{\mu_0I}{2b}$, | ||
| + | we get a formula for pressure:$$P=\frac{\mu_0I^2}{8b^2}$$ | ||
| + | Hooke's law: | ||
| + | $$\frac{\Delta}{a}=\frac{P}{E}$$ | ||
| + | $$\Delta=\frac{\mu_0aI^2}{8Eb^2}$$ | ||
| + | б)$$P=\frac{B^2}{2\mu_0}$$ | ||
| + | $$B=\sqrt{2\mu_0P}$$ | ||
| + | $$B_1\approx10Тл$$ | ||
| + | $$B_2\approx35Тл$$ | ||
| + | |||
| + | #### Answer | ||
| + | |||
| + | [Insert a concise answer or boxed result] | ||
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| ### Statement | |||
| $9.3.6.$ [Insert the problem statement] | |||
| ### Solution | |||
| а)Energy density (magnetic pressure) is calculated using the formula $$P=w=\frac{B^2}{2\mu_0}$$ | |||
| Considering the induction to be constant throughout the entire cross-section and equal to $B=\frac{\mu_0I}{2b}$, | |||
| we get a formula for pressure:$$P=\frac{\mu_0I^2}{8b^2}$$ | |||
| Hooke's law: | |||
| $$\frac{\Delta}{a}=\frac{P}{E}$$ | |||
| $$\Delta=\frac{\mu_0aI^2}{8Eb^2}$$ | |||
| б)$$P=\frac{B^2}{2\mu_0}$$ | |||
| $$B=\sqrt{2\mu_0P}$$ | |||
| $$B_1\approx10Тл$$ | |||
| $$B_2\approx35Тл$$ | |||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||