Новое решение
en/9.3.19.md
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| + | ### Statement | ||
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| + | $9.3.19.$ [Insert the problem statement] | ||
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| + | ### Solution | ||
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| + | In Problem 9.3.17, a formula was obtained for the induction inside the plate. On its axis, it is zero and increases linearly with distance from the plate: $$B=\mu_0 j x$$ | ||
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| + | This means that, moving along the x-axis, only the transverse plate makes a contribution, and when we leave it, the induction becomes constant and equal to $$B_{max}=\frac{\mu_0 j h}{2}$$ | ||
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| + | #### Answer | ||
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| + | [Insert a concise answer or boxed result] | ||
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| ### Statement | |||
| $9.3.19.$ [Insert the problem statement] | |||
| ### Solution | |||
| In Problem 9.3.17, a formula was obtained for the induction inside the plate. On its axis, it is zero and increases linearly with distance from the plate: $$B=\mu_0 j x$$ | |||
| This means that, moving along the x-axis, only the transverse plate makes a contribution, and when we leave it, the induction becomes constant and equal to $$B_{max}=\frac{\mu_0 j h}{2}$$ | |||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||